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x → 1 lim ​ 4 x 2 + 5 x − 9 3 x 2 + 4 x − 7 ​ = ....

  1. begin mathsize 14px style 10 over 13 end style

  2. begin mathsize 14px style 9 over 13 end style

  3. begin mathsize 14px style 13 over 9 end style

  4. begin mathsize 14px style 13 over 11 end style

  5. begin mathsize 14px style 11 over 13 end style

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Dengan begitu, opsi jawban yang tepat adalah A.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 of fraction numerator 3 x squared plus 4 x minus 7 over denominator 4 x squared plus 5 x minus 9 end fraction end cell equals cell limit as x rightwards arrow 1 of fraction numerator left parenthesis 3 x plus 7 right parenthesis left parenthesis x minus 1 right parenthesis over denominator left parenthesis 4 x plus 9 right parenthesis left parenthesis x minus 1 right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator 3 x plus 7 over denominator 4 x plus 9 end fraction end cell row blank equals cell fraction numerator 3 plus 7 over denominator 4 plus 9 end fraction end cell row blank equals cell 10 over 13 end cell end table end style

Dengan begitu, opsi jawban yang tepat adalah A.

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HItunglah nilai limit fungsi-fungsi berikut. x → 1 lim ​ 2 − x + 3 ​ 1 − x 2 ​

2

4.2

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