Roboguru

Pertanyaan

begin mathsize 14px style 9. space Diketahui space g left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell m x cubed minus 1 over 12 space comma space pada space left square bracket 2 comma 3 right square bracket end cell row cell 0 comma space ditempat space lain end cell end table close. Tentukan space nilai space m space agar space g left parenthesis x right parenthesis space merupakan space fungsi space kerapatan space probabilitas. end style   

  1. ...space 

  2. ...undefined 

Pembahasan Soal:

begin mathsize 14px style Nilai space fungsi space kerapatan space probabilitas adalah space 1 integral subscript 2 superscript 3 m x cubed minus 1 over 12 d x equals 1 open square brackets m over 4 x to the power of 4 minus 1 over 12 x close square brackets subscript 2 superscript 3 equals 1 open square brackets m over 4 open parentheses 3 close parentheses to the power of 4 minus 1 over 12 open parentheses 3 close parentheses close square brackets minus open square brackets m over 4 open parentheses 2 close parentheses to the power of 4 minus 1 over 12 open parentheses 2 close parentheses close square brackets equals 1 fraction numerator 81 m over denominator 4 end fraction minus 3 over 12 minus fraction numerator 16 m over denominator 4 end fraction plus 2 over 12 equals 1 fraction numerator 65 m over denominator 4 end fraction minus 1 over 12 equals 1 fraction numerator 65 m over denominator 4 end fraction equals 1 plus 1 over 12 fraction numerator 65 m over denominator 4 end fraction equals 13 over 12 m equals fraction numerator begin display style bevelled 13 over 12 end style over denominator 65 divided by 4 end fraction m equals 52 over 780   end style   

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 11 Februari 2021

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