Pertanyaan

x → − 2 lim 6 + x − x 2 2 − 2 − x = ...

$x \to - 2 lim \frac{2 - 2 - x}{6 + x - x ^{2}} = ...$

H. Eka

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

nilai

nilai $limit as x rightwards arrow negative 2 of space fraction numerator 2 minus square root of 2 minus x end root over denominator 6 plus x minus x squared end fraction equals 1 over 20$

Pembahasan

Nilai dari limit fungsi aljabar tersebut dapat ditentukan dengan metode perkalianakar sekawan sebagai berikut. Dengan demikian, nilai

Nilai dari limit fungsi aljabar tersebut dapat ditentukan dengan metode perkalian akar sekawan sebagai berikut.

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow negative 2 of space fraction numerator 2 minus square root of 2 minus x end root over denominator 6 plus x minus x squared end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator 2 minus square root of 2 minus x end root over denominator 6 plus x minus x squared end fraction cross times fraction numerator 2 plus square root of 2 minus x end root over denominator 2 plus square root of 2 minus x end root end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator 4 minus open parentheses 2 minus x close parentheses over denominator open parentheses 3 minus x close parentheses open parentheses 2 plus x close parentheses open parentheses 2 plus square root of 2 minus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator 2 plus x over denominator open parentheses 3 minus x close parentheses open parentheses 2 plus x close parentheses open parentheses 2 plus square root of 2 minus x end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator 1 over denominator open parentheses 3 minus x close parentheses open parentheses 2 plus square root of 2 minus x end root close parentheses end fraction end cell row blank equals cell fraction numerator 1 over denominator open parentheses 3 plus 2 close parentheses open parentheses 2 plus square root of 4 close parentheses end fraction end cell row blank equals cell fraction numerator 1 over denominator 5 times 4 end fraction end cell row blank equals cell 1 over 20 end cell end table$

Dengan demikian, nilai $limit as x rightwards arrow negative 2 of space fraction numerator 2 minus square root of 2 minus x end root over denominator 6 plus x minus x squared end fraction equals 1 over 20$