Pertanyaan

( p + q p 2 − q 2 ) 2 p 2 − q 2 p + q = …

$(\frac{p ^{2} - q ^{2}}{p + q})^{2} \frac{p + q}{p ^{2} - q ^{2}} = \dots$

D. Enty

Master Teacher

Jawaban terverifikasi

Jawaban

tidak ada jawaban yang tepat.

Pembahasan

Perhatikan penyederhanaan bentuk aljabar berikut. Jadi, tidak ada jawaban yang tepat.

Perhatikan penyederhanaan bentuk aljabar berikut.

$table attributes columnalign right center left columnspacing 0px end attributes row cell square root of open parentheses fraction numerator p squared minus q squared over denominator p plus q end fraction close parentheses squared end root square root of fraction numerator p plus q over denominator p squared minus q squared end fraction end root end cell equals cell square root of open parentheses fraction numerator p squared minus q squared over denominator p plus q end fraction close parentheses squared times open parentheses fraction numerator p plus q over denominator p squared minus q squared end fraction close parentheses end root end cell row blank equals cell square root of open parentheses fraction numerator up diagonal strike p squared minus q squared end strike over denominator up diagonal strike p plus q end strike end fraction close parentheses times open parentheses fraction numerator p squared minus q squared over denominator p plus q end fraction close parentheses times open parentheses fraction numerator up diagonal strike p plus q end strike over denominator up diagonal strike p squared minus q squared end strike end fraction close parentheses end root end cell row blank equals cell square root of fraction numerator p squared minus q squared over denominator p plus q end fraction end root end cell row blank equals cell square root of fraction numerator open parentheses p minus q close parentheses up diagonal strike open parentheses p plus q close parentheses end strike over denominator up diagonal strike p plus q end strike end fraction end root end cell row blank equals cell square root of p minus q end root end cell end table$

Jadi, tidak ada jawaban yang tepat.