Roboguru

4.    Penalaran Hasil dari  adalah …

Pertanyaan

4.    Penalaran
Hasil dari begin mathsize 14px style square root of 24 open parentheses square root of 8 minus 2 square root of 3 close parentheses plus fraction numerator 24 over denominator square root of 2 end fraction end style adalah …

  1. begin mathsize 14px style 8 square root of 2 plus 12 square root of 3 end style

  2. begin mathsize 14px style 8 square root of 3 minus 12 square root of 2 end style

  3. begin mathsize 14px style 8 square root of 2 end style

  4. begin mathsize 14px style 8 square root of 3 end style

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 24 open parentheses square root of 8 minus 2 square root of 3 close parentheses plus fraction numerator 24 over denominator square root of 2 end fraction end cell row blank equals cell 2 square root of 6 open parentheses 2 square root of 2 minus 2 square root of 3 close parentheses plus fraction numerator 24 over denominator square root of 2 end fraction cross times fraction numerator square root of 2 over denominator square root of 2 end fraction end cell row blank equals cell 4 square root of 12 minus 4 square root of 18 plus 12 square root of 2 end cell row blank equals cell 8 square root of 3 minus 12 square root of 2 plus 12 square root of 2 end cell row blank equals cell 8 square root of 3 end cell end table end style

Jadi, jawaban yang tepat adalah D.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 01 April 2021

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved