Roboguru

100 mL larutan asam yang mempunyai pH=1 dicampur dengan 50 mL larutan basa yang mempunyai pH=13. Hitung pH larutan yang terjadi!

Pertanyaan

100 mL larutan asam yang mempunyai pH=1 dicampur dengan 50 mL larutan basa yang mempunyai pH=13. Hitung pH larutan yang terjadi!space 

Pembahasan Soal:

Menentukan mol masing-masing larutan

mol larutan pH=1

Larutan ini memiliki pH=1, maka larutan tersebut bersifat asam dan dapat ditentukan nilai konsentrasi H to the power of plus sign yaitu sebagai berikut:

table attributes columnalign right center left columnspacing 0px end attributes row pH equals 1 row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 1 end exponent space M end cell row blank blank blank row cell mol space open square brackets H to the power of plus sign close square brackets end cell equals cell V space open square brackets H to the power of plus sign close square brackets cross times M space open square brackets H to the power of plus sign close square brackets end cell row cell mol space open square brackets H to the power of plus sign close square brackets end cell equals cell 100 space mL cross times 0 comma 1 space M end cell row cell mol space open square brackets H to the power of plus sign close square brackets end cell equals cell 10 space mmol end cell end table     

mol larutan pH=13

Larutan ini memiliki pH=13, maka larutan tersebut bersifat basa dan dapat ditentukan nilai konsentrasi O H to the power of minus sign yaitu sebagai berikut:

table attributes columnalign right center left columnspacing 0px end attributes row pH equals 13 row pOH equals cell 14 minus sign 13 end cell row pOH equals 1 row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 1 end exponent space M end cell row blank blank blank row cell mol space open square brackets O H to the power of minus sign close square brackets end cell equals cell V space open square brackets O H to the power of minus sign close square brackets cross times M space open square brackets O H to the power of minus sign close square brackets end cell row cell mol space open square brackets O H to the power of minus sign close square brackets end cell equals cell 50 space mL cross times 0 comma 1 space M end cell row cell mol space open square brackets O H to the power of minus sign close square brackets end cell equals cell 5 space mmol end cell end table     

 

Reaksi pencampuran larutan


Pada reaksi tersebut, yang tersisa adalah ion H to the power of plus sign maka larutan bersifat asam.

open square brackets H to the power of plus sign close square brackets equals a cross times M subscript a open square brackets H to the power of plus sign close square brackets equals a cross times fraction numerator mol space sisa over denominator V space total end fraction open square brackets H to the power of plus sign close square brackets equals 1 cross times fraction numerator 5 cross times 10 to the power of negative sign 3 end exponent space mol over denominator 0 comma 15 space L end fraction open square brackets H to the power of plus sign close square brackets equals 3 comma 4 cross times 10 to the power of negative sign 2 end exponent space M  pH equals minus sign log space open square brackets H to the power of plus sign close square brackets pH equals minus sign log space open square brackets 3 comma 4 cross times 10 to the power of negative sign 2 end exponent space M close square brackets pH equals 2 minus sign log space 3 comma 4 

Jadi pH campurannya adalah bold pH bold equals bold 2 bold minus sign bold log bold space bold 3 bold comma bold 4.space 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Mei 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved