Roboguru

....

Pertanyaan

begin mathsize 14px style integral left parenthesis 8 x cubed minus 3 x squared plus 4 x minus 1 right parenthesis space d x equals end style....

Pembahasan Video:

Pembahasan Soal:

Konsep integral tak tentu:

integral a x to the power of n equals fraction numerator a over denominator n plus 1 end fraction x to the power of n plus 1 end exponent plus C comma space C element of R comma space n not equal to 1

Penyelesaian

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell integral open parentheses 8 x cubed minus 3 x squared plus 4 x minus 1 close parentheses d x end cell row blank equals cell fraction numerator 8 over denominator 3 plus 1 end fraction x to the power of 3 plus 1 end exponent minus fraction numerator 3 over denominator 2 plus 1 end fraction x to the power of 2 plus 1 end exponent plus fraction numerator 4 over denominator 1 plus 1 end fraction x to the power of 1 plus 1 end exponent minus x plus C end cell row blank equals cell 8 over 4 x to the power of 4 minus 3 over 3 x cubed plus 4 over 2 x squared minus x plus C end cell row blank equals cell 2 x to the power of 4 minus x cubed plus 2 x squared minus x plus C space comma space C element of R end cell end table

Jadi, Error converting from MathML to accessible text..

 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 01 Agustus 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved