Pertanyaan

( 4 p 3 q 2 2 a 3 b c 5 ) 3 = ... .

$(\frac{2 a ^{3} b c ^{5}}{4 p ^{3} q ^{2}})^{3} = ...$ .

$fraction numerator 6 a to the power of 9 space b cubed space c to the power of 15 over denominator 12 p to the power of 6 space q to the power of 6 end fraction$
$fraction numerator 8 a to the power of 9 space b cubed space c to the power of 15 over denominator 64 p to the power of 9 space q to the power of 6 end fraction$
$fraction numerator 8 a to the power of 6 space b cubed space c to the power of 15 over denominator 64 p to the power of 9 space q to the power of 5 end fraction$
$fraction numerator 16 a to the power of 9 space b cubed space c to the power of 15 over denominator 64 p to the power of 9 space q to the power of 6 end fraction$

Y. Fathoni

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta.

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Ingat kembali konsep bilangan berpangkat. Akan ditentukan bentuk sederhana dari . Diperoleh . Jadi, jawaban yang tepat adalah B.

Ingat kembali konsep bilangan berpangkat.

Akan ditentukan bentuk sederhana dari $open parentheses fraction numerator 2 a cubed b c to the power of 5 over denominator 4 p cubed q squared end fraction close parentheses cubed$ .

$table attributes columnalign right center left columnspacing 2px end attributes row cell open parentheses fraction numerator 2 a cubed b c to the power of 5 over denominator 4 p cubed q squared end fraction close parentheses cubed end cell equals cell open parentheses 2 a cubed b c to the power of 5 close parentheses cubed over open parentheses 4 p cubed q squared close parentheses cubed end cell row blank equals cell fraction numerator open parentheses 2 close parentheses cubed open parentheses a cubed close parentheses cubed open parentheses b close parentheses cubed open parentheses c to the power of 5 close parentheses cubed over denominator open parentheses 4 close parentheses cubed open parentheses p cubed close parentheses cubed open parentheses q squared close parentheses cubed end fraction end cell row blank equals cell fraction numerator 2 cubed a to the power of 3 cross times 3 end exponent b cubed c to the power of 5 cross times 3 end exponent over denominator 4 cubed p to the power of 3 cross times 3 end exponent q to the power of 2 cross times 3 end exponent end fraction end cell row blank equals cell fraction numerator 8 a to the power of 9 b cubed c to the power of 15 over denominator 64 p to the power of 9 q to the power of 6 end fraction end cell end table$

Diperoleh $open parentheses fraction numerator 2 a cubed b c to the power of 5 over denominator 4 p cubed q squared end fraction close parentheses cubed equals fraction numerator 8 a to the power of 9 b cubed c to the power of 15 over denominator 64 p to the power of 9 q to the power of 6 end fraction$ .

Jadi, jawaban yang tepat adalah B.