Roboguru

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Pertanyaan

begin mathsize 14px style limit as straight x rightwards arrow 3 of fraction numerator straight x squared minus space 13 x plus 30 over denominator straight x squared plus 2 straight x minus 15 end fraction end style = ....

Pembahasan Soal:

soal di atas merupakan limit tak tentu fungsi aljabar yang penyelesaiannya menggunakan faktorisasi. Perhatikan perhitungan berikut !
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell limit as straight x rightwards arrow 3 of fraction numerator straight x squared minus space 13 straight x plus 30 over denominator straight x squared plus 2 straight x minus 15 end fraction end cell equals cell limit as straight x rightwards arrow 3 of fraction numerator up diagonal strike left parenthesis straight x minus 3 right parenthesis end strike left parenthesis straight x minus 10 right parenthesis over denominator up diagonal strike left parenthesis straight x minus 3 right parenthesis end strike left parenthesis straight x plus 5 right parenthesis end fraction end cell row blank equals cell fraction numerator left parenthesis 3 minus 10 right parenthesis over denominator left parenthesis 3 plus 5 right parenthesis end fraction end cell row blank equals cell fraction numerator negative 7 over denominator 8 end fraction end cell row blank equals cell negative 7 over 8 end cell end table end style   
 

Jadi,  begin mathsize 14px style limit as straight x rightwards arrow 3 of fraction numerator straight x squared minus 13 straight x plus 30 over denominator straight x squared plus 2 straight x minus 15 end fraction equals negative 7 over 8 end style  

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 12 Maret 2021

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