Roboguru

= ....

Pertanyaan

begin mathsize 14px style limit as straight x rightwards arrow 3 of fraction numerator straight x squared plus 2 straight x minus 8 over denominator straight x squared plus straight x minus 6 end fraction end style = ....

Pembahasan Soal:

soal di atas merupakan limit tak tentu fungsi aljabar yang penyelesaiannya menggunakan faktorisasi.

Perhatikan perhitungan berikut !
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell limit as straight x rightwards arrow 3 of fraction numerator straight x squared plus 2 straight x minus 8 over denominator straight x squared plus straight x minus 6 end fraction end cell equals cell limit as straight x rightwards arrow 3 of fraction numerator open parentheses straight x plus 4 close parentheses up diagonal strike open parentheses straight x minus 2 close parentheses end strike over denominator open parentheses straight x plus 3 close parentheses up diagonal strike open parentheses straight x minus 2 close parentheses end strike end fraction end cell row blank equals cell fraction numerator open parentheses 3 plus 4 close parentheses over denominator open parentheses 3 plus 3 close parentheses end fraction end cell row blank equals cell 7 over 6 end cell end table end style  
 

Jadi,  begin mathsize 14px style limit as straight x rightwards arrow 3 of fraction numerator straight x squared plus 2 straight x minus 8 over denominator straight x squared plus straight x minus 6 end fraction equals 7 over 6 end style  

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 12 Maret 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved