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....

open vertical bar fraction numerator 1 over denominator 1 plus square root of 3 end fraction close vertical bar equals....

  1. 1 half open parentheses 1 minus square root of 3 close parentheses

  2. 1 half open parentheses square root of 3 minus 1 close parentheses

  3. square root of 3 minus 1

  4. 1 minus square root of 3

  5. negative square root of 3

Jawaban:

Nilai mutlak dari bilangan positif atau nol sama dengan bilangan itu sendiri. Nilai mutlak dari bilangan negatif pasti bernilai positif, karena negatif dari bilangan negatif adalah bilangan positif.

Rasionalkan operasi tersebut.

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar fraction numerator 1 over denominator 1 plus square root of 3 end fraction cross times fraction numerator 1 minus square root of 3 over denominator 1 minus square root of 3 end fraction close vertical bar end cell equals cell open vertical bar fraction numerator 1 minus square root of 3 over denominator 1 squared minus open parentheses square root of 3 close parentheses squared end fraction close vertical bar end cell row blank equals cell open vertical bar fraction numerator 1 minus square root of 3 over denominator 1 minus 3 end fraction close vertical bar end cell row blank equals cell open vertical bar fraction numerator 1 over denominator negative 2 end fraction open parentheses 1 minus square root of 3 close parentheses close vertical bar end cell row blank equals cell open vertical bar 1 half open parentheses square root of 3 minus 1 close parentheses close vertical bar end cell end table

Karena operasi di dalam mutlak bernilai positif, maka didapatkan :

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open vertical bar 1 half open parentheses square root of 3 minus 1 close parentheses close vertical bar end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 1 half end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses square root of 3 minus 1 close parentheses end cell end table

Maka, table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar fraction numerator 1 over denominator 1 plus square root of 3 end fraction close vertical bar end cell equals cell 1 half open parentheses square root of 3 minus 1 close parentheses end cell end table

Oleh karena itu, jawaban yang benar adalah B

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