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= ....

Pertanyaan

begin mathsize 14px style limit as straight x rightwards arrow 3 of fraction numerator straight x squared plus straight x minus 20 over denominator straight x squared plus 3 straight x minus 10 end fraction end style = ....

Pembahasan Video:

Pembahasan Soal:

Dengan menggunakan metode substitusi pada limit, maka diperoleh :

table attributes columnalign right center left columnspacing 2px end attributes row cell limit as straight x rightwards arrow 3 of fraction numerator straight x squared plus straight x minus 20 over denominator straight x squared plus 3 straight x minus 10 end fraction end cell equals cell fraction numerator 3 squared plus 3 minus 20 over denominator 3 squared plus 3 times 3 minus 10 end fraction end cell row blank equals cell fraction numerator 9 plus 3 minus 20 over denominator 9 plus 9 minus 10 end fraction end cell row blank equals cell fraction numerator negative 8 over denominator 8 end fraction end cell row blank equals cell negative 1 end cell end table  
 

Jadi,  begin mathsize 14px style limit as straight x rightwards arrow 3 of fraction numerator straight x squared plus straight x minus 20 over denominator straight x squared plus 3 straight x minus 10 end fraction end style = begin mathsize 14px style negative 1 end style 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 21 Juli 2021

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