dimasukkan 9 g NaCl ke dalam 900 ml air. Massa jenis air = 1 g/ml dan Kf air = 1.86 C/molal. Tentukan titik beku larutan tersebut

delta Tf = molalitas X kf Tf = 0 drajat celsius - delta Tf dik : m nacl = 9 gr ro. = 1 gr / ml kf. = 1.86 C/molal Tf. = ......? jawab. ro = gr : volume 1. = m air : 900 m air = 900 gr molalitas = gr nacl : Mr nacl X 1000: gr ait ( pelarut ) m = 9:58.5 X 1000:900 = 9000 : 52650 = 0.17 delta Tf = 0.17 X 1.86 = 0.3162 jadi Tf ( titik beku lar.) = 0 - 0.316 = - 0.3162